x(x+3)=15^2

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Solution for x(x+3)=15^2 equation:



x(x+3)=15^2
We move all terms to the left:
x(x+3)-(15^2)=0
We add all the numbers together, and all the variables
x(x+3)-225=0
We multiply parentheses
x^2+3x-225=0
a = 1; b = 3; c = -225;
Δ = b2-4ac
Δ = 32-4·1·(-225)
Δ = 909
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{909}=\sqrt{9*101}=\sqrt{9}*\sqrt{101}=3\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{101}}{2*1}=\frac{-3-3\sqrt{101}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{101}}{2*1}=\frac{-3+3\sqrt{101}}{2} $

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